Re: problem with inline function

[Mike Amos <yl_mra@xxxxxxxxx>]

Please refer to the ILE C/C++ Programmer's Guide. In the 'Coding a C++ 
Program" section, look at the example code for the inline keyword. Note 
that the inline prototype is the expanded function; there is no function 
defined further down in the code. Please try changing your code to

// Prototypes

static inline int add_value(int x, int y)
{
	return x + y;
};


int main(int argc, char **argv)
{
        int returnValue = 0;

        int x = 2;
        int y = 0;

        int z = add_value(x, y);

	  return returnValue;

}

There is also the possibility that the static declaration with the 
inline is confusing the compiler. Technically, the function cannot be 
both static and inline as static sets aside space at compile/link time 
whereas inline inserts the inlined function into the source code at 
compile time.

Finally, try removing the semicolon from the end of the function as in

static inline int add_value(int x, int y)
{
	return x + y;
}; <==

I've seen this result in errors with other compilers. It is needed as 
I've shown above - where the definition is included in the prototype 
section, but not otherwise. Your code would become:


// Prototypes
int add_value(int x, int y);

int main(int argc, char **argv)
{
        int returnValue = 0;

        int x = 2;
        int y = 0;

        int z = add_value(x, y);

	return returnValue;
}

static inline int add_value(int x, int y)
{
	return x + y;
}  /* <== The semicolon is removed */

Regards,
Mike


Schmidt, Mihael wrote:
> Hi,
>
> I got a little problem with inlining a function in the following example code:
>
>
> // Prototypes
> int add_value(int x, int y);
>
>
> int main(int argc, char **argv)
> {
>         int returnValue = 0;
>
>         int x = 2;
>         int y = 0;
>
>         int z = add_value(x, y);
>
> 	  return returnValue;
>
> }
>
> static inline int add_value(int x, int y)
> {
> 	return x + y;
> };    
>
> If i try to compile this I get: