|
Brad-Try something like this: You will have to change your input date to be
something like
19990901.
DRealDate DS
D ISODate D DATFMT(*ISO) INZ(D'1940-01-01')
D ISOCC 2 0 Overlay(ISODate:1)
D ISOYY 2 0 Overlay(ISODate:3)
D ISOCCYY 4 0 Overlay(ISODate:1)
D ISOMM 2 0 Overlay(ISODate:6)
D ISODD 2 0 Overlay(ISODate:9)
.....
C eval InputDate = ISODate
* Calculate the last date of the month.
C eval ISOMM = ISOMM + 1
C If ISOMM > 12
C eval ISOMM = 1
C eval ISOCCYY = ISOCCYY + 1
C endif
C eval ISODD = 1
C ISODate subdur 1:*D Date
C move Date ENDOFMTH
Terry Richardson
Sr. P/A
The Orvis Company, Inc.
802-362-8663
-----Original Message-----
From: Brad McDaniel [SMTP:BMCDANIEL@ABSBC.ORG]
Sent: Wednesday, October 13, 1999 9:31 AM
To: 'midrange-l@midrange.com'
Subject: Last Day of Last Month
I am writing some CL's to automate some monthly jobs that are
usually submitted through user menus. This particular CL submits a job with
the prior month and year as the parms (let's say &YEAR (4) and &MONTH (2)).
Then, the CL does a STRQMQRY with the year, month, and day of the last day
of that month. Does anyone have a sample of the easiest way to figure out
the last day of a particular month (i.e. if run today, the year and month
would be 1999 09, and the CL would need to pass 19990930 to the query.)?
I know the method for passing parms with STRQMQRY, I am just
wondering if anyone has some code laying around that gives you the last day
of the month (accounting for leap years also).
Thanks
Brad McDaniel
Information Services
Annuity Board, SBC
<http://www.absbc.org> http://www.absbc.org
214-720-6546
+---
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