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----- Original Message ----- From: Peter Dow <pcdow@MailAndNews.com> To: <MIDRANGE-L@midrange.com> Sent: Saturday, October 21, 2000 10:42 AM Subject: Re: Factors and Terms > From: "Leif Svalgaard" <leif@leif.org> > > it has only one factor, namely 7. If you want to call 1 a factor of 7, > then > > I'll argue that 7 has seven factors, viz. 7, 1, 1, 1, 1, 1, 1, because > > undeniably 7 = 7*1*1*1*1*1*1. > > Why stop there? You could have an infinite number of *1's there. just my point, but David has a limit on the size of a posting so my example wouldn't make it through <g> > > > > A factorization of a number by convention excludes the divisor 1, > > in order to maintain the desirable property that every number larger > > than 1 can be written as a unique product of prime numbers raised > > to integral powers. The factorization of 6 is 6 = 2**1 * 3**1, of 28 is > > 28 = 2**3 * 7**1, of 7 is 7 = 7**!, etc. > > 28 = 2**3 * 7**1? That *must* be fuzzy math!<G> jeez, you guys actually read this drivel? even the last example was wrong (hint ! should be 1). +--- | This is the Midrange System Mailing List! | To submit a new message, send your mail to MIDRANGE-L@midrange.com. | To subscribe to this list send email to MIDRANGE-L-SUB@midrange.com. | To unsubscribe from this list send email to MIDRANGE-L-UNSUB@midrange.com. | Questions should be directed to the list owner/operator: david@midrange.com +---
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