|
Gotta learn to read the problem first.
Brute force (like the MI version): 5 minutes writing, 2.8 seconds running
d theString s 50
d theResult s 50
d loopLimit s 10u 0 inz(100000)
d timestp s z
d fr s 10u 0
d to s 10u 0
d at s *
d chr s 1a based(at)
c time timestp
c timestp dsply 'BUCK'
c do loopLimit
C eval theString = ' this is a test '
C ' ' check theString fr
C ' ' checkr theString to
C eval theResult = theString
* prime the translate loop
C eval at = %addr(theResult) + fr - 1
C fr do to
C if chr = ' '
C eval chr = '_'
C endif
C eval at = at + 1
c enddo
c enddo
c time timestp
c timestp dsply 'BUCK'
c eval *InLR=*On
This should perform worse the longer the string gets. I thought of a
different way; to scan for the blanks. 15 minutes of coding (including
debugging) and 4 seconds to run. It should scale better for longer strings
though.
d theString s 50
d theResult s 50
d loopLimit s 10u 0 inz(100000)
d timestp s z
d fr s 10u 0
d to s 10u 0
d i s 10u 0
c time timestp
c timestp dsply 'BUCK'
c do loopLimit
C eval theString = ' this is a test '
C ' ' check theString fr
C ' ' checkr theString to
C eval theResult = theString
C eval i = fr
C dow i <= to
C eval i = %scan(' ': theResult: i)
c if i = 0 or
c i > to
c leave
C endif
c*
C eval %subst(theResult: i: 1) = '_'
C eval i = i + 1
c enddo
c enddo
c time timestp
c timestp dsply 'BUCK'
c eval *InLR=*On
Buck
> -----Original Message-----
> From: Leif Svalgaard
> Sent: Monday, March 19, 2001 11:45 AM
> To: MIDRANGE-L@midrange.com
> Subject: Re: Web apps on the AS/400
>
> you got it backwards. The original string does not have underscores
> in it, but embedded spaces...
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