RE: Any way in the CL program to find the length of the character datastored in a variable?

["Gregory A. Garner" <ggarner_gds@xxxxxxxxxxxxxx>]

Create a loop and test the substring positions of the field for blanks
starting from the first position.  Add 1 to a counter until you hit a blank
position. The counter is the length.  If it is a multi word field (city
field where city name could be two or more word, i.e. Fort Smith), start the
search from the right. Test for a character. When one is found, subtract one
from the counter then subtract the counter form the field length.


Gregory A. Garner
Garner Data Systems, Inc.
4270 Grand Teton Parkway
Suwanee, GA 30024
770 845 9636



-----Original Message-----
From: midrange-l-bounces@xxxxxxxxxxxx
[mailto:midrange-l-bounces@xxxxxxxxxxxx]On Behalf Of Vernon Hamberg
Sent: Friday, March 04, 2005 11:36 PM
To: Midrange Systems Technical Discussion
Subject: RE: Any way in the CL program to find the length of the
character datastored in a variable?


This is an API - you can probably find it on google, or go to
www.iseries.ibm.com/infocenter and look under programming, then APIs

HTH
Vern

At 10:26 PM 3/4/2005, you wrote:
>Thanks Doug....
>Is it an API?... Wats the Parm list for this...  Coudnt get any in my
>manuals...
>
>Thanks
>Siva.
>
>
>Doug Hart <DougHart@xxxxxxxxxxxx> wrote:
>
>QCLSCAN
>
>
>---
>Doug Hart
>
>
>
>-----Original Message-----
>From: midrange-l-bounces@xxxxxxxxxxxx
>[mailto:midrange-l-bounces@xxxxxxxxxxxx] On Behalf Of Siva
>Sent: Friday, March 04, 2005 11:02 PM
>To: MIDRANGE-L@xxxxxxxxxxxx
>Subject: Any way in the CL program to find the length of the character
>datastored in a variable?
>
>
>Is there any way in the CL program to find the length of the character data
>stored in a variable?
>
>I find there is no direct CL command to acheive this... may be some
>roundabout way there to do this... but nothing striking at this moment....
>
>i think of some prgm calls with the required variable as the parm and the
>receiviong prgm process the variable etc... but couldnt get any logic here
>:-)......
>
>
>Thanks
>Siva.
>
>
>
>
>
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