AW: DATE Datatype in SQL View

["BirgittaHauser" <Hauser@xxxxxxxxxxxxxxx>]

Hi,

Character strings in one of the following formats can always 

Mit freundlichen Grüßen / Best regards

Birgitta Hauser

"Shoot for the moon, even if you miss, you'll land among the stars." (Les
Brown)

"If you think education is expensive, try ignorance." (Derek Bok)

"What is worse than training your staff and losing them?  Not training them
and keeping them!"



-----Ursprüngliche Nachricht-----
Von: midrange-l-bounces@xxxxxxxxxxxx
[mailto:midrange-l-bounces@xxxxxxxxxxxx] Im Auftrag von Elvis Budimlic
Gesendet: Sunday, February 25, 2007 08:03
An: 'Midrange Systems Technical Discussion'
Betreff: RE: DATE Datatype in SQL View


Let's say you have your alpha date in the following format:

02-25-2007

and your current job is set to *MDY with date separator being '/', something
like this would work:

CREATE VIEW mylib/myview AS 
  (SELECT DATE(REPLACE(myfield,'-','/')) AS myDateField FROM mylib/myfile)

or if you don't have access to REPLACE function on the version of OS you're
running:

CREATE VIEW mylib/myview AS
  (SELECT DATE(SUBSTR(myfield,1,2) || '/' || SUBSTR(myfield,4,2) || '/'
SUBSTR(myfield,7,4)) AS myDateField FROM mylib/myfile)

That aside, perhaps your alpha format resembles *ISO (YYYY-MM-DD). In that
case, simply casting to DATE may work, i.e.:

CREATE VIW mylib/myview AS
  (SELECT DATE(myfield) AS myDateField FROM mylib/myfile)

HTH

Elvis

Celebrating 10-Years of SQL Performance Excellence

-----Original Message-----
From: midrange-l-bounces+ebudimlic=centerfieldtechnology.com@xxxxxxxxxxxx
[mailto:midrange-l-bounces+ebudimlic=centerfieldtechnology.com@xxxxxxxxxxxx]
On Behalf Of Ron Adams
Sent: Sunday, February 25, 2007 12:07 AM
To: Midrange Systems Technical Discussion
Subject: Re: DATE Datatype in SQL View

Currently, it is Alpha 10.

Funny, I was just looking thru some Centerfield's newsletters and the
examples you had in there.



On 2/24/07, Elvis Budimlic <ebudimlic@xxxxxxxxxxxxxxxxxxxxxxxxx> wrote:
> What's your field's current format?
>
> Celebrating 10-Years of SQL Performance Excellence
>
>
> --
> Ron Adams