RE: [Fwd: regular expressions, I am puzzled]

["Evan Harris" <spanner@xxxxxxxxxx>]

Hi Terry

My first thought would be to use 2 regexes - the first to extract the substring you want to perform the second on.

So in your case, something like

"n(u)(t*i)"
"(t*)(i)"

But I donât get what you are trying to accomplish so I have no idea if this is applicable.

After reading the manual extract posted doing it this way may at leads give me mortals a chance of understanding what you are trying to do.
 

Regards
Evan Harris


-----Original Message-----
From: midrange-l-bounces@xxxxxxxxxxxx [mailto:midrange-l-bounces@xxxxxxxxxxxx] On Behalf Of Terrence Enger
Sent: Tuesday, 4 August 2009 7:21 a.m.
To: Midrange Systems Technical Discussion
Subject: Re: [Fwd: regular expressions, I am puzzled]

On Mon, 2009-08-03 at 12:22 -0500, Scott Klement wrote:
> Hi Terry,
>
> Have you read the following (from regexec topic in the "ILE C Runtime 
> Library" manual):
>
>     If subexpression i is contained within another subexpression j, and i
>     is not contained within any other subexpression that is contained
>     within j, and a match of subexpression j is reported in pmatch[j],
>     then the match or non-match of subexpression i reported in pmatch[i]
>     will be as described in 1. and 2. above, but within the substring
>     reported in pmatch[j] rather than the whole string.

No, I should have been following that.  Thank you.

In a simple case, I see that behaviour:  regex "nu((t*)(i))" and string
"nuttin" return
    rm_so  rm_eo
    -----  -----
    2      5
    0      2
    2      3

Introduction of a set of parentheses earlier in the regex should not, as
I read it, change the result returned for the last two subexpressions.
But the result for regex "n(u)((t*)(i))" is
ï    rm_so  rm_eo
    -----  -----
    1      2
    2      5
    1      3
    3      4

Thank you for your help, Scott.  Any further thoughts?

Terry.