Do you care what value of plbbg1 is selected for the duplicate employee
record?
If not, then use any of the aggregate functions to 'pick' one, i.e.:
SELECT eeun, eedpt, plbemp, eenam, max(plbbg1) as plbbg1, plbhrs , plbptp
FROM PRLBH, EEMP WHERE PLBEMP = EEENO and
PLBPTP in('CO','OH', '6D','7D','OG') and
EETDT = 0 and EEDPT = '081' and PLBWDT = 20090115
GROUP BY PLBEMP,EENAM,PLBBG1, PLBHRS , PLBPTP,EEUN, EEDPT
Order by PLBEMP
Hth, Elvis
Celebrating 11-Years of SQL Performance Excellence on IBM i, i5/OS and
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-----Original Message-----
Subject: Need help with SQL group by
I have a sql statement that I cannot get to work the way I want.
The statement as it currently exists is.
SELECT eeun, eedpt, plbemp, eenam, plbbg1, plbhrs , plbptp
FROM PRLBH, EEMP WHERE PLBEMP = EEENO and
PLBPTP in('CO','OH', '6D','7D','OG') and
EETDT = 0 and EEDPT = '081' and PLBWDT = 20090115
GROUP BY PLBEMP,EENAM,PLBBG1, PLBHRS , PLBPTP,EEUN, EEDPT
Order by PLBEMP
My results look like this
Eeun eedpt plbemp eenam plbbg1 plbhrs plbptp
Y 081 890 Smith, Mike 081 4.00 OH
Y 081 890 Smith, Mike 081 1.00 OH
Y 081 1160 Mead,Kurt 081 3.50 OH
Y 081 1160 Mead,Kurt 081 1.50 OH
I am trying to get 1 record per employee, but I cannot find the correct
solution.
What am I missing here?
Mike
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