RE: Help with SQL statement

["Smith, Mike" <Mike_Smith@xxxxxxxxxxxxxxxx>]

Thanks all. 
I hate it when I don't see things that are obvious, but you don't see it
because you have been looking at it too much.  
It is working now.  

-----Original Message-----
From: midrange-l-bounces@xxxxxxxxxxxx
[mailto:midrange-l-bounces@xxxxxxxxxxxx] On Behalf Of Vern Hamberg
Sent: Wednesday, September 09, 2009 8:30 AM
To: Midrange Systems Technical Discussion
Subject: Re: Help with SQL statement

Hi Mike

Then you have to leave PLBPTP out of the group by list. Then either you
put an aggregate function (MAX or MIN, e.g.) on it, or you leave it also
off the field list.

Anyhow, here're my thoughts -

-- to keep PLBPTP in the field list --
SELECT eeun, eedpt, plbemp, eenam, plbbg1, sum(plbhrs), (min)plbptp FROM
   .
   .
   .
GROUP BY PLBEMP,EENAM ,EEDPT, EEUN, PLBBG1 ORDER BY EEDPT,PLBEMP

-- to take PLBPTP off the field list --
SELECT eeun, eedpt, plbemp, eenam, plbbg1, sum(plbhrs) FROM
   .
   .
   .
GROUP BY PLBEMP,EENAM ,EEDPT, EEUN, PLBBG1 ORDER BY EEDPT,PLBEMP


HTH
Vern
Smith, Mike wrote:
> I have the following SQL statement.  
>    
>
> That produces results like this 
> Eedpt     plbemp      eenam
> plbbg1       eeun      sum(plbhrs)	         PLBPTP
> 091         165     SMITH MICHAEL A	                     091
> Y 	 16.00         470.00      OH
> 091         165     SMITH MICHAEL A	                     091
> Y 	  5.50          470.00      6D
> 091         165     SMITH MICHAEL A                            091
> Y         16.00         470.00      6C
>
> I get 3 records because there are three different values of PLBPTP    
>
> I can't get my grouping to work so that I get 1 record that looks like

> this
>
> 091	165	SMITH, MICHAEL A		        091	Y
> 37.50	     470.00
>
> Can you suggest a way to make this work?
>
> Thanks
>
> Mike
>
>
>
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