Re: iconv query

[Bruce Vining <bvining@xxxxxxxxxxxxxxx>]

True, but in that case you're passing a pointer (address) and not the
variable. For instance on the call to fscanf() you need to pass an array
name (address of first element) or the address operator (&) with the correct
operand/variable. The arguments (pointers in this case) themselves are
passed by value. The variable addressed by the pointer can certainly be
changed, no argument there. My confusion is with the assertion that structs
(or anything else for that matter) are not passed by value (by default)
when calling a function using C.

On Fri, Feb 5, 2010 at 9:51 AM, Dennis Lovelady <iseries@xxxxxxxxxxxx>wrote:

> > I'm confused. With C, when calling a function, all argument
> > (parameter) passing is is by value. That's how C is defined. By
> > convention
> > many functions may pass by value a pointer to the struct, and with
> > arrays it
> > gets a little muddy as an array is really a pointer to the first
> > element
> > (though the pointer again is passed by value), but that's an
> > implementation
> > decision of the function provider, not C.
>
> Not quite.  When you pass a pointer to a variable (as you would, say, with
> fscanf), you find that your variable can (will) be changed.  You're not
> comparing apples with apples.
>
> Dennis Lovelady
> http://www.linkedin.com/in/dennislovelady
> --
> "No matter what side of an argument you're on, you always find some people
> on your side that you wish were on the other side."
>        -- Jascha Heifetz
>
>
>
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