Re: rclactgrp

["Mark S. Waterbury" <mark.s.waterbury@xxxxxxxxxxxxx>]

 Hi, Len:

There are many things that could be going on here.

You did not say what language(s) these programs are written in. For example:

Is Program A written in CLP (an OPM *PGM that runs only in the *DFTACTGRP)?

    -or-

Is Program A written as a CLLE (ILE CL) program, how is it created, with 
CRTBNDCL,
or with CRTCLMOD and bound CRTPGM?  And what activation group does "A" 
run in?

Also, (perhaps more important), exactly how does Program A call Program B?

You might try this experiment (assuming CL):

    DCL &PGMB    *CHAR 10 VALUE('B')
    ...
    CALL    PGM(&PGMB) PARM( ...)

This will force a "resolve" and full dynamic call on each call, whereas:

    CALL    PGM(B) PARM( ... )

NOTE: the CL compiler emits code in program "A" to resolve the pointer 
to program "B" just
      once, retains that pointer, and re-uses it, so it would still 
point to the replaced
      object "Q123456789" now in QRPLOBJ, even after you have 
recompiled program "A".

Let us know if this experiment helps you to resolve this "mystery."

All the best,

Mark S. Waterbury

> On 9/30/2010 5:00 PM, Len Lester wrote:
>    Program A calls Program B which calls Program C.
>
> Programs B and C are in an activation group.
>
> Program A can be instructed to RCLACTGRP the group which contains B and C.
>
> If I re-compile program C the replacement object is in use until I
> instruct program A to RCLACTGRP before calling program B.
>
> After that, the new version of program C  is in use.
>
> This doesn't work for program B.  THe replacement object stays in use
> and the new version of the program is not used.
>
> If I re-compile C again and instruct program A again to RCLACTGRP, the
> new version of program C is put into use but the replacement object for
> B remains on the call stack.
>
> The WRKJOB command verifies that B and C are in the same activation
> group and the program A has deleted the activation group.
>
> Why won't the new version of program B come into use?
>
>
> Both Program B and Program C call program D which is in the default
> activation group.
>
> Other programs besides A call Program B.