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On 8/31/2011 4:34 PM, Dennis Lovelady wrote:list
If you want to avoid converting decimal to hex, make it a 1 byte integerfield
1I 0 Inz(97)
Does that work? I thought you had to specify signed and unsigned
integers in number of digits:
3u0 or 3i0 = 1 byte
5u0 or 5i0 = 2 bytes
10u0 or 10i0 = 4 bytes
20u0 or 20i0 = 8 bytes
And with anything other than 3u0 you have to worry about sign and also
endian-ness. I generally stick with 3u0 when defining bytes with
decimal values.
Joe
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