With the left outer join specified, TableB.Fld1 will be NULL if there's no
matching record in B.

Charles


On Thu, Jun 20, 2013 at 1:24 PM, Michael Ryan <michaelrtr@xxxxxxxxx> wrote:

Hey Vern -

But the condition isn't that TableB.Fld1 is null, it's that the key value
TableA.Fld1 is found in TableB.


On Thu, Jun 20, 2013 at 1:01 PM, Vern Hamberg <vhamberg@xxxxxxxxxxxxxxx
wrote:

Hi Michael

That's what this should do - a LEFT OUTER JOIN will give you all records
from TableA and TableB, if there is a match - NULLs, otherwise.

Give it a try. You might like it almost as much as 7Up!

Vern

----- Original Message -----
Thanks guys...I didn't explain myself well. I want to display the values
from TableA, and an 'X' if the key in TableA is found in TableB.


On Thu, Jun 20, 2013 at 12:27 PM, Vern Hamberg <vhamberg@xxxxxxxxxxxxxxx
wrote:

Left outer JOIN, I think.

select tablea.fld1, tablea.fld2, case when TableB.fld1 is null then ' '
else 'X' end from tablea join tableb on tablea.fld1 = tableb.fld1

Check the syntax of the CASE - I'm doing this from memory.

HTHAW (hope this helps and works)
Vern

----- Original Message -----
Here's what I want to do...TableA has 4 columns. TableB shares a key
value
with TableA. I want to produce this output in a select statement (to be
used from PHP fwiw):

TableA.Fld1 TableA.Fld2 'X' (if TableA.Fld1 is in TableB).

I've been trying combinations of a CTE, CASE, and exists, but I can't
get
this to work. I'd like:

A1 A2
A3 A4 X
A5 A6 X
A7 A8

IOW, I want the values for TableA to show up, and an X if the
corresponding
key value is in TableB. This has to be easier than I'm making it out to
be.

Thanks!
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