From my point of view, the code should not reset the value of SQLSTATE
before you evaluate another SQL statement, and what the C source code
version does is that: it first sets the value of SQLSTATE to '00000' just
before you execute your second IF statement, making it a true condition and
not respecting the previous value of the last SQL statement. That's what
I'm saying, to me that is bad logic. But, that's how it is and we
already know how to get over it.

JS


El jue, 27 feb 2025 a las 13:29, Daniel Gross (<daniel@xxxxxxxx>) escribió:

Hi Javier,

I don't think we have a bug here.

The evaluation of an expression in SQL is something, that can result in an
error.

Think of an SQL SELECT statement, where you do a "division by zero" in the
SELECT clause. You will receive a SQLSTATE of '01564' - this is the result
of the failed evaluation of the expression - not the result of the SELECT.
The SELECT only passes this SQLSTATE back to the caller.

The evaluation of an expression sets the SQLCODE - this is only
consequential from SQL's point-of-view.

IMHO - this all works as intended - only because the intention does not
align with our reception, doesn't make it a bug.

HTH
Daniel


Am 27.02.2025 um 19:20 schrieb Javier Sanchez <
javiersanchezbarquero@xxxxxxxxx>:

What still makes it "weird", this behavior in SQL P/L. For some reason
IBM
decided to let the C preprocessor code it like that, but using our logic
discussed here, it should be "a big bug". Good to know to rather use
save
variables.

JS


El jue, 27 feb 2025 a las 12:06, Daniel Gross (<daniel@xxxxxxxx>)
escribió:

Absolutely right!

If that is coded as embedded SQL in RPG, you would simply code the IF as
RPG - and the RPG compiler generates code to compare the (RPG) variable
SQLSTATE without evaluating it in SQL.

So indeed the "same" code would work as RPG with embedded SQL.

Regards,
Daniel


Am 27.02.2025 um 18:34 schrieb Javier Sanchez <
javiersanchezbarquero@xxxxxxxxx>:

Maybe you didn't debug the C source listing, what I found is that the
first
IF statement generates code to call DB2 with the query and is sets
SQLSTATE
to what in internal variable used in a data structure for that call,
which
at that moment is a NOT FOUND condition ('02000'), and just after
comparing
the value against '02000' it unconditionally sets SQLSTATE to '00000'
just
before the second IF statement. SQLSTATE is then '00000' which
evaluates
to
TRUE in the second IF.. And it then yet again sets it to '00000' after
evaluating it.

What you could expect with an SQLRPGLE embedded SQL program, may not be
the
same though. Because the SQLSTATE and SQLCODE variables not only are
automatically created by the precompiler, but the generated RPG code
does
not change the value of SQLSTATE "before" you use it again in another
SQL
statement.

So your code maybe does work as you expect in an SQLRPGLE program with
the
same SQL statements.
Test it, you may find this is true.

JS


El jue, 27 feb 2025 a las 10:04, Daniel Gross (<daniel@xxxxxxxx>)
escribió:
Hi,
After reading the docs completely, it seems to be very clear. The page
in
InfoCenter is:
https://www.ibm.com/docs/en/i/7.5?topic=pl-if-statement
And Martijn you already quoted the right part:
... when the statement that follows the IF statement is executed, the
SQLSTATE and SQLCODE SQL variables reflect the result of evaluating
the
search conditions of that IF statement.
The SQLSTATE reflect the result of "evaluating the search conditions"
-
so
evaluating
SqlState = '02000'
as an logical expression, results in an SQLSTATE = '00000' - which
seems
absolutely plausible.
Birgitta you are absolutely right - the (SQL-)IF is translated to a
C-IF -
but the expression is still evaluated by SQL - and that evaluation
could go
wrong (like with an unknown variable or something) and therefore could
also
result in a SQLSTATE <> '00000'.
So I was wrong - it's not the IF statement itself, that sets the
SQLSTATE
- but the evaluation of the (logical) expression does.
HTH
Daniel
Am 27.02.2025 um 16:33 schrieb Birgitta Hauser <
Hauser@xxxxxxxxxxxxxxx>:
SQL code is converted into C-Code with embedded SQL ... and only the
embedded SQL Statements produce SQLCODE and SQLSTATE.
There is a native C command for an IF, so the IF-Statement is
converted
in
the C-IF ... which is NO longer an SQL statement and consequently
does
not
produce/change the SQLCODE and/or SQLSTATE.
Mit freundlichen Grüßen / Best regards
Birgitta Hauser
Modernization – Education – Consulting on IBM i
Database and Software Architect
IBM Champion since 2020
"Shoot for the moon, even if you miss, you'll land among the stars."
(Les
Brown)
"If you think education is expensive, try ignorance." (Derek Bok)
"What is worse than training your staff and losing them? Not training
them
and keeping them!"
"Train people well enough so they can leave, treat them well enough
so
they
don't want to. " (Richard Branson)
"Learning is experience … everything else is only information!"
(Albert
Einstein)
-----Original Message-----
From: MIDRANGE-L <midrange-l-bounces@xxxxxxxxxxxxxxxxxx> On Behalf
Of
Martijn van Breden
Sent: Thursday, 27 February 2025 16:18
To: Midrange Systems Technical Discussion <
midrange-l@xxxxxxxxxxxxxxxxxx
Subject: Re: When is SqlState reset?
Thanks for the reactions, I looked up documentation in the SQL
reference.
It states:
Considerations for SQLSTATE and SQLCODE SQL variables: When the first
SQL-procedure-statement in the IF statement is executed, the SQLSTATE
and
SQLCODE SQL variables reflect the result of evaluating the
search-conditions
of that IF statement. If an IF statement does not include an ELSE
clause
and
none of the search-conditions evaluate to true, then when the
statement
that
follows the IF statement is executed, the SQLSTATE and SQLCODE SQL
variables
reflect the result of evaluating the search conditions of that IF
statement.
As I read it, it doesn't say that the IF itself is changing the value
of
SQLSTATE, but that's what Javier found. I changed my production code
to
save
the SqlState value in a seperate variable, but it still seems weird
to
me.
I'll get in touch with IBM about the documentation
Kind regards
Martijn van Breden
lead software architect
My understanding is that SQLCODE and SQLSTATE are set to the result
after
each SQL statement, which probably means reset at the start of each
SQL
statement. Since this code is SQl procedural language, it looks like
IF
is
an SQL statement.
I just googled this and ran across and SAP question about it - seems
there
might have been a change in behavior there, and a change to what is
really
the SQL standard.
Please remember that many things in SQL are the same in different
implementations, but I am not saying that SAP should be used
conclusively to
determine what is going on with IBM i - this was just an interesting
similarity.
--
*Regards*
*Vern Hamberg*
<cid:part1.VByWODzW.Wwn8nQpF@centurylink.net>
On 2/24/2025 9:09 AM, Javier Sanchez wrote:
Interesting. And yes! Weird.
I replicated your code and it's like you say.
I debugged the procedure using the "C" source code, and I could see
that, YES it changes the value of SQLSTATE to '00000' just after
your
first "if", it does it using this:
memset(SQLSTATE, '0', 5);
Then it immediately also resets SQLCODE to zero.
Additionally, when you declared the SQLSTATE variable, it actually
did
not set it to blanks as your default clause specified. I inspected
it
and it rather initialized it with the value '00000'.
This explains the "weird" behavior.
HTH
JS
El lun, 24 feb 2025 a las 8:07, Martijn van Breden (<
m.vanbreden@xxxxxxxxxxxxxxxxxxxxxxxxxx>) escribió:
Hi all
I ran into some peculiar piece of code that didn't do what I
expected
and decided to run a small test.
The goal is to see if SqlState is being reset in an if-statement.
My
human brain says it shouldn't be reset in the example code below
begin
declare sqlState char(5) default '';
declare myLocalVar char(1) default 'X';
select IBMREQD into myLocalVar from sysibm.sysdummy1 where 0 = 1;
if SqlState = '02000' then
if SqlState = '00000' then
call systools.lprintf ('2:' || SqlState || myLocalVar);
end if;
end if;
end;
SqlState and myLocalVar are declared
I select IBMREQD from sysdummy1 with a where condition that assures
it's not found (the value in sysdummy1 is 'Y'). My SqlState is
therefore 02000, I checked that. So, my subsequent if-statement is
then
true.
In my mind the inner if-statement can't be true if the outer is, so
it should never produce an entry in the joblog.
However, it does give "2:00000X" in the joblog.
I'm aware that the call to lprintf will alter the SqlState value,
but I only expect a new value for SqlState after the call.
It seems that the if statement itself modifies SqlState or am I
overlooking something? It just seems weird...
Kind regards,
Martijn van Breden
lead software architect
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