|
Yes, its a little more complicated than simply using a SUBDUR.
However, consider this: If you used SUBDUR to calculate hours, mins
and seconds all in one statement, what would the result field be?
It couldn't just be another "Time" field, because a time field must
always contain a valid time of day, and with subdur you can
(at least potentially) calculate negative numbers.
At any rate, doing what you want to do isnt particularly difficult.
heres a code sample:
D T1 S T
D T2 S T
D TotSec S 15 0
D Hours S 2 0
D Mins S 2 0
D Secs S 2 0
C eval T1 = T'08.00.00'
C eval T2 = T'16.30.00'
C T2 SUBDUR T1 TotSec:*S
C TotSec div 3600 Hours
c mvr TotSec
c TotSec div 60 Mins
c mvr Secs
Hope that helps,
Scott Klement
Information Systems Manager
Klement's Sausage Co, Inc.
Chuck Lewis <CLEWIS@IQUEST.NET> wrote:
> Hi Folks ]
>
> Maybe I'm making this harder than it needs to be (hope so ]) but I
> need
> to be able to tell the "interval in time measurements of time (i.e.
> 8:00
> to 4:30 is 8 hours and 30 minutes in "human time" and appear
> clueless...
>
> I've looked at the *SUBDR deal but it appears you have to do it for
> hours and minutes separately (?).
>
> Thanks in advance ]
>
> Chuck
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