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Let's say I have these three fields defined...
d MMDDCCYY s d inz datfmt(*USA)
d todayISO s 8s0 inz(20020819)
d todayUSA s 8s0 inz
What is the free-format way to convert the date-field to a numbeic... :
-- The old way to do it was :
c *ISO MOVE todayISO MMDDCCY
c MOVE MMDDCCYY todayUSA
-- How would the above be changed...
-- We have someone here who found a C program that would do the trick, but
I wasn't sure if there was an easier way...
David L. Mosley, Jr.
Systems Analyst
2000 CentreGreen Way
Suite 250
Cary, NC 27513
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