RE: Convert hex to char (cvtch)

["Smith, Nelson" <NSmith@xxxxxxxxxxx>]

The data structure and the documentation for the exit point I'm trying to
work with actually define the field as being binary AND 4 bytes long.  It is
not an integer, so I didn't want to use 10I 0.  It contains hex codes that
are to be compared to X'1800', X'1803', etc.  I'm not sure yet if those hex
codes are in the first two bytes of the field or the last two.  

At this point, I'm just trying to get a look at the hex codes that actually
come through from the exit point call to see what they look like.  I was
trying to convert the entire 4-byte field (positions 29-32 of the data
structure) to character just to include it in a log file I can review. Since
this is coming in from ODBC connections, it is extremely hard to debug
interactively.

> -----Original Message-----
> From: Joe Pluta [SMTP:joepluta@PlutaBrothers.com]
> Sent: Thursday, January 30, 2003 3:58 PM
> To:   RPG programming on the AS400 / iSeries
> Subject:      RE: Convert hex to char (cvtch)
> 
> > From: Smith, Nelson
> >
> > I'm trying to use cvtch to convert hex data to character, and I'm
> > getting a space offset error.
> 
> This is the dreaded 'B' binary data type issue.
> 
> D  hexFunctCode                  4B 0
> 
> The above does NOT define a binary field 4 bytes long.  It defines a
> binary
> field which can hold four digits of information, which is actually a
> two-byte field.  So you want to be converting a 2-byte hex field into a
> 4-byte character field.  Change your code as shown:
> 
> 
> D  hexFunctCode                  4B 0
> D  alp2HexBytes                  2A   OVERLAY(ds_ZDAQ0200:29)
> 
> D  alp4CharBytes  S              4A   INZ
> 
> C                   CALLP     cvtch(%ADDR(alp4CharBytes)
> C                                  :%ADDR(alp2HexBytes)
> C                                  :%Len(alp4CharBytes)  )
> 
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