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Eve, here's one method, (using SQL):
D Number S 16P 8 Inz(3.75)
D Character S 20A
D Result S Like(Character)
/Free
// Convert numeric to a character
Character = %Char(Number);
/End-Free
// Use SQL string functions to save some coding
C/Exec Sql
C+ Set :Result = Trim(Both '0' From Trim(Both ' ' From :Character))
C/End-Exec
/Free
// Display results to confirm
Result = '<' + %Trim(Result) + '>';
Dsply Result '*REQUESTER';
*InLR = *On;
/End-Free
Brian Parkins
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