Hi Jon -

 >> That really simplies the equation.

Does it?  I can't help wondering.  If you "simplify" to the point that a
knowledge of algebra is needed before you can understand the relationship of
the code to the original requirement ... then haven't you obfuscated rather
than simplified?

The version ( ( FieldA - 1 ) / FieldA ) * 100 is a direct representation of
the original requirement and there can't be a lot of difference performance
wise.

I agree with you, except for one issue which I haven't seen mentioned (or missed seeing). Because of the intermediate field length issues on divide operations, I would move the divide to the end ...

( ( FieldA - 1) * 100 ) / FieldA

Since the compiler cannot generate a field with an infinite number of decimal places, it is always best to eliminate or minimize divide operations, and keep them as late in the equation as possible.

Ken
http://www.ke9nr.net/
Opinions expressed are my own and do not necessarily represent the views of my employer or anyone in their right mind.


This thread ...

Follow-Ups:

Follow On AppleNews
Return to Archive home page | Return to MIDRANGE.COM home page

This mailing list archive is Copyright 1997-2026 by midrange.com and David Gibbs as a compilation work. Use of the archive is restricted to research of a business or technical nature. Any other uses are prohibited. Full details are available on our policy page. If you have questions about this, please contact [javascript protected email address].

Operating expenses for this site are earned using the Amazon Associate program and Google Adsense.