|
Cheers Birgitta,
Thats worked sort of, below is a snap shot of data, but I wasnt expecting
any dates earlier than 2001-11-01;
FLTITM MYDATE
1993-02-20
V906195 1996-06-18
1994-11-10
1996-08-05
V027902 1992-07-02
1995-12-07
1993-06-30
1994-02-23
1997-10-07
So close yet so far...
"HauserBirgitta"
<Hauser@SSS-Softwa
re.de> To
Sent by: "RPG programming on the AS400 /
rpg400-l-bounces+m iSeries" <rpg400-l@xxxxxxxxxxxx>
crangle=cinetic-la cc
ndis.co.uk@midrang
e.com Subject
Re: 8s0 field into a date using
SQL
01/11/2006 10:20
Please respond to
RPG programming on
the AS400 /
iSeries
<rpg400-l@midrange
.com>
Hi,
before you can use a the scalar function SUBSTR you have to convert your
numeric values into a character string by using the scalar function DIGITS.
Also YYYY/MM/DD is not a valid character representation of a date. Valid
representations are YYYY-MM-DD, MM/DD/YYYY, DD.MM.YYYY.
Date is a reserved word for SQL and cannot be used as column name. You
either have to use a different name or to embedd date in double quotes
"date". If you use double quotes, field names are case sensitive i.e.
"Date"
<> "date" <> "DATE".
Instead of the double pipes you should prefer concat, because the double
pipes are not international and cannot be used with all languages.
SELECT fltitm,
substr(digits(faildt), 1, 4) concat '-' concat
substr(digits(faildt), 5, 2) concat '-' concat
substr(digits(faildt), 7, 2) as Mydate
from faultlog WHERE DATE(substr(digits(faildt),1,4) concat '-'
concat
substr(digits(faildt), 5, 2) concat '-'
concat
substr(digits(faildt), 7, 2)) <=
CURRENT_DATE - 5 years
Last comment:
For the query above a table scann will be used, because access paths
(indexes or DDS described logical files) are only used when build over the
original fields in the physical files. By using a scalar function in you
case DATE(), SUBSTR(), DIGITS() an access path over faildt cannot be used.
Mit freunlichen Grüßen / Best regards
Birgitta Hauser
"Shoot for the moon, even if you miss, you'll land among the stars." (Les
Brown)
"If you think education is expensive, try ignorance." (Derek Bok)
----- Original Message -----
From: <mcrangle@xxxxxxxxxxxxxxxxxxxx>
To: <rpg400-l@xxxxxxxxxxxx>
Sent: Wednesday, November 01, 2006 10:59
Subject: 8s0 field into a date using SQL
I have a 8s0 field (FAILDT), with data stored as 20061231.
I want to convert to a date field, then select records where FAILDT <=
CURRENT DATE - 5 Years.
Obviously missing something in this statement...
SELECT fltitm,
substr(faildt,1,4) || '/' ||
substr(faildt,5,2) || '/' ||
substr(faildt,7,2) as date
from faultlog WHERE DATE(substr(faildt,1,4) || '/' ||
substr(faildt,5,2) || '/' ||
substr(faildt,7,2)) <= CURRENT DATE - 5
years
Once this is cracked I can hopefully get my boss to convert to SQL and
ILE
from rpg400.... Thanks Martin -- This is the RPG programming on the AS400 / iSeries (RPG400-L) mailing
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