Re: Using %editc()

[Johnny Johnson <jjohnson@xxxxxxxxxxxx>]

I believe Peter is somewhat correct...try splitting it.

D int3            s           3i 0

int3   = %int(HSISN3) + 1;
HSISN3  = %editc(int3 :'X');






                                                                           
             Peter Levy                                                    
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             11/21/2006 10:33          Re: Using %editc()                  
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Just off the top of my head I'm guessing that the %INT() BIF outputs a
binary integer that is probably a ten digit number. %EDITC() probably
outputs a temporary value that is ten characters in length and when you
EVAL it to a three character field it gets cut off. You could try using
EVALR.

Don Wereschuk wrote:
> Hi All:   I'm trying to use %editc() to add 1 to a 3 character field but
> it is not working quite right. I just can't see what I am doing wrong.
>
>
>
> The code is as follows:
>
>
>
>                             HSISN3 = %editc((%int(HSISN3) + 1):'X');
>
>
>
> HSISN3 is defined as 3 character. The initial value is '001'. I was
> hoping after the calc that the value would be '002'. Instead I get
> '000'.
>
>
>
> The program is compiled as *ZONED. Can anyone help?   TIA
>
>
>
> ******************************************
>
> Don Wereschuk
>
> ISD  - Programmer/Analyst
>
> Simcoe Parts Service Inc.
>
> Phone:   705-435-7814          Ex: 302
>
> Fax:         705-435-6746
>
> mailto:dwereschuk@xxxxxxxxxxxxxxx
>
> ******************************************
>
> "Save the Cheerleader - Save the world"  - Hiro Nakamura
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