Re: translation in /free??

[Ken Sims <mdrg6315@xxxxxxxxxxx>]

Hi Booth -

On Mon, 09 Apr 2007 13:55:35 -0500, Booth Martin <booth@xxxxxxxxxxxx>
wrote:

> It worries me when I see these kinds of precision expected in what 
> appears to be fairly large number.
>
> It looks like minutes are being divided by 60 to give fractional hours, 
> and then the number of calls are being divided by that answer?  Would it 
> make more accuracy to do the math the other way around?  Divide the 
> calls by the big number, and then convert that by dividing by 60?   Or 
> divide in the other direction and give an answer of average minutes/call?

You're right.  The double divide is just asking for problems because
of the intermediate result of @time / 60 (unless you put it inside a
%DECH as Scott suggested).

Since a divide by a divide is a multiply, personally I would make it
eval(h) @callshr = (@calls * 60) / @time
which eliminates the intermediate divide completely but still gives
calls per hour.

Ken
http://www.kensims.net/
Opinions expressed are my own and do not necessarily represent the views 
of my employer or anyone in their right mind.