|
Since you now longer have an *INLR in the new program model
how does the
storage ever get released? Only the ending of the job?
Seems kind of strange. Shouldn't it always be 0 with the new
program model
because the storage is released on each call?
Thanks.
--
As an Amazon Associate we earn from qualifying purchases.
This mailing list archive is Copyright 1997-2025 by midrange.com and David Gibbs as a compilation work. Use of the archive is restricted to research of a business or technical nature. Any other uses are prohibited. Full details are available on our policy page. If you have questions about this, please contact [javascript protected email address].
Operating expenses for this site are earned using the Amazon Associate program and Google Adsense.