Re: Losing decimal precision...

[Alan Campin <alan0307d@xxxxxxxxx>]

Yea, define the variable as 4p3. If you 12.3 on a calculator and divide by
100 you get .123 but you have the variable defined 1 decimal point so it
truncates off.

On Fri, Nov 6, 2015 at 2:59 PM, Robert Rogerson <rrogerson@xxxxxxxxxxx>
wrote:

> Hi, how do I code this statement so num1 = .123 not .1?
>
> D num1            s              7p 3
> D num2            s              4p 1
>
> /Free
>   num2 = 12.3;
>   num1 = num2 / 100;
> /Endif
>
>
> Can I do this without creating a temp variable?
>
> D num1            s              7p 3
> D num2            s              4p 1
> d num3            s              4p 3
>
> /Free
>   num2 = 12.3;
>   num3 = num2 / 100;
>   num1 = num3;
> /Endif
>
> Thanks,  I think it's one of those Friday afternoon things....
>
> Rob
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