I an trying to use a LIKE in my SQL to allow searching for the result.

From Run SQL Scripts this works exactly as expected

select * from mfsdta/mfsdebpf
where debcoy = 1 and debac like 'A%' and debact = 'A'
fetch first 10 rows only;

But from PHP running on the IBMi using the toolkitservice I have

$conn = getToolkitServiceForCurrentUser();
$sql = "select * from "
. MFS_LIBRARY . ".MFSDEBPF "
. " where DEBCOY = ? and DEBAC like ? and debact =
? "
. " order by DEBAC "
. " fetch first 10 rows only";

$values = array();
$values[0] = $company;
$values[1] = $search . "%";
$values[2] = $status;
print_r($values);
$stmt = prepareAndExecute($conn, $sql, $values);

The $values array have these values

Array ( [0] => 1 [1] => A% [2] => A )

No errors are received but no records either.

If I change the where to use and DEBAC >= ? then I get records returned
so it has to be the way I am formatting the variable with the % sign.

As a separate question I can't find any log file that may hold the answer
- any suggestions ????

Thanks

Don



--
This email has been scanned for computer viruses. Although MSD has taken reasonable precautions to ensure no viruses are present in this email, MSD cannot accept responsibility for any loss or damage arising from the use of this email or attachments..

As an Amazon Associate we earn from qualifying purchases.

This thread ...


Follow On AppleNews
Return to Archive home page | Return to MIDRANGE.COM home page

This mailing list archive is Copyright 1997-2024 by midrange.com and David Gibbs as a compilation work. Use of the archive is restricted to research of a business or technical nature. Any other uses are prohibited. Full details are available on our policy page. If you have questions about this, please contact [javascript protected email address].

Operating expenses for this site are earned using the Amazon Associate program and Google Adsense.