Re: RegExp I give up

[Terrence Enger <tenger@xxxxxxxxxxxxxxxx>]

On Wed, 2009-07-22 at 08:04 -0700, Spencer Elliott wrote:
> Hi,
> I have the following regular expression:
> ^(MDB)[\w\W]*(Final.PDF|Final.pdf)$

I am familiar with \w as shorthand for [_A-Za-z0-9] and the web site you
cite below accepts space or hyphen and I know not what else for \W.
Anyway, the expression 
    [-A-Za-z0-9_ ]+
matches the middle part of your test input.

> This expression test as true against the following string:
> MDB MO3-09 Final.PDF
> at http://www.regular-expressions.info/javascriptexample.html
>
> I run the same expression and string through the iSeries RegExp APIs and 
> it fails(returns 1).
>
> Does anyone have any idea where there is a online test that matches the 
> IBM APIs or can figure out what I am doing incorrectly?

Even a quick reference guide to the details on the iSeries would be a
help.  I am sure I am just overlooking it, but it is frustrating to be
reduced to experimentation.

Cheers,
Terry.

> BTW: The OCEAN conference was great!
>
> My program works with another expression to test email addresses.
> ^[A-Za-z0-9._%+-]+@[A-Za-z0-9.-]+\.[A-Za-z]{2,6}$
>
> Thanks,
> Spencer
>
>
> ---snip---
> /*---( Compile pattern )---*/
> rc = regcomp(&preg, wrkPattern, REG_EXTENDED);
> if (rc != 0) {
>     regerror(rc, &preg, errMsg, sizeof(errMsg));
>     PatError(100, (char *) pattern, (char *) errMsg);
>
>     regfree(&preg);
>
>     if (matchString != inpString) {
>        free((void *) matchString);
>        matchString = NULL;
>     }
>     return (0);
> }
>
> /*---( Run Pattern )---*/
> if ( (rc = regexec(&preg, matchString, nmatch, pmatch, 0)) != 0 ) {
>     regerror(rc, &preg, errMsg, sizeof(errMsg));
> ---snip---