Wouldn't the number of digits = number of bits (for a binary number) (Ignoring a sign bit)?
Paul E Musselman
PaulMmn@xxxxxxxxxxxxx
-----Original Message-----
From: MIDRANGE-L <midrange-l-bounces@xxxxxxxxxxxx> On Behalf Of dlclark@xxxxxxxxxxxxxxxx
Sent: Thursday, November 29, 2018 12:23 PM
To: Midrange Systems Technical Discussion <midrange-l@xxxxxxxxxxxx>
Subject: Re: UIM More Options
OK, I found my problem. I didn't understand what BIN 15 meant in
terms of number of bytes of storage for the dialog variable. I thought 15
was the number of digits, but I guess it is the number of bits. So, I
should have had a 2-byte binary number and I had tried a 4 byte and an 8
byte. Silly me.
Sincerely,
Dave Clark
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